(x^2-4)^2=8*x+1

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Solution for (x^2-4)^2=8*x+1 equation:



(x^2-4)^2=8x+1
We move all terms to the left:
(x^2-4)^2-(8x+1)=0
We get rid of parentheses
(x^2-4)^2-8x-1=0
We add all the numbers together, and all the variables
-8x+(x^2-4)^2-1=0
We move all terms containing x to the left, all other terms to the right
-8x+(x^2-4)^2=1

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